自动化立体仓库 - WMS系统
pang.jiabao
2025-04-30 abb9b5c51d8a20be68b64e0c4a9620f6578d2e3a
src/main/java/com/zy/asrs/task/handler/GhjtHandler.java
@@ -212,7 +212,7 @@
            String staLocNo = null;
            Integer wrkCount = wrkMastMapper.selectCount(new EntityWrapper<WrkMast>().eq("crn_no", i));
            if(wrkCount > 0) {
                log.warn("{}号堆垛机已存在任务",i);
//                log.warn("{}号堆垛机已存在任务",i);
                continue;
            }
            // 根据堆垛机号查询到对应的深库位和浅库位  深库位4*n-3和4*n 浅库位4*n-2和4*n-1
@@ -241,16 +241,16 @@
            }
            // 没有找到源库位
            if (sourceLocNo == null) {
                log.warn("没有找到源库位,堆垛机:{}",i);
//                log.warn("没有找到源库位,堆垛机:{}",i);
                continue;
            }
            // 寻找一个备货的目标库位,先深后浅
            List<LocMast> locMasts1 = locMastMapper.selectList(new EntityWrapper<LocMast>().eq("loc_sts", "O").eq("crn_no", i).in("row1", s1, s2)
                    .le("bay1", columnNum));
                    .le("bay1", columnNum).orderBy("lev1,bay1,row1"));
            if (locMasts1.isEmpty()) {
                // 深库位为空了,取浅库位
                List<LocMast> locMasts2 = locMastMapper.selectList(new EntityWrapper<LocMast>().eq("loc_sts", "O").eq("crn_no", i).in("row1", q1, q2)
                        .le("bay1", columnNum));
                        .le("bay1", columnNum).orderBy("lev1,bay1,row1"));
                if (!locMasts2.isEmpty()) {
                    staLocNo = locMasts2.get(0).getLocNo();
                }
@@ -396,6 +396,16 @@
        // 寻找一箱一卷的,没有理货的,不在备货区的物料明细
        List<LocDetl> tallyGoosList = locDetlMapper.selectTallyGoosList(columnNum);
        // 过滤掉木箱规格宽度大于600的(大于600一个托盘只能放一箱)
        tallyGoosList = tallyGoosList.stream().filter(locDetl -> {
            String[] split = locDetl.getColor().split("\\*");
            if (split.length == 3) { // 高度也要低于614才能理货
                return Integer.parseInt(split[1]) <= 600 && Integer.parseInt(split[2]) <= 614;
            } else {
                return false;
            }
        }).collect(Collectors.toList());
        // 寻找满足理货条件的两个木箱
        LocDetl leftLocDetl = null;
        LocDetl rightLocDetl = null;